Question #122935

On R^n show that || . ||∞ ≤ || . ||2

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1
Expert's answer
2020-06-22T18:02:49-0400

Let,xRnx\in \mathbb{R}^n such that x=(x1,,xn)x=(x_1,\dots,x_n) ,thus

x2=k=1nxi2||x||_2=\sqrt{\sum_{k=1}^{n}|x_i|^2}

And,

x=max1in{xi}||x||_{\infty}=\max_{1\leq i \leq n}\{|x_i|\}

Let, WLOG , x=xk||x||_{\infty}=x_k for some k{1,,n}k\in\{1,\dots,n\} but also note that


x2=xk2x12++xk2++xn2=x22    xx2||x||_{\infty}^2=x_k^2\leq x_1^2+\dots+x_k^2+\dots+x_n^2=||x||_2^2\\ \iff ||x||_{\infty}\leq ||x||_2

Hence, we are done.


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