Question #115713
Prove that an open interval in R is an open set and a closed intervals is a closed set
1
Expert's answer
2020-05-18T18:59:53-0400

1)Let (a,b)(a,b) be an open interval. Take arbitrary x(a,b)x\in(a,b). We have Bδ(x)(a,b)B_\delta(x)\subset(a,b),where δ=min{xa,bx}\delta=\min\{x-a,b-x\}, so xx is an interior point of (a,b)(a,b).

Since we take arbitrary x(a,b)x\in(a,b), we obtain that every point of (a,b)(a,b) is an interior point of (a,b)(a,b), so (a,b)(a,b) is an open set.

2)Let [a,b][a,b] be a closed interval. Take arbitrary xR[a,b]x\in\mathbb R\setminus[a,b]. We have Bδ(x)R[a,b]B_\delta(x)\subset\mathbb R\setminus[a,b], where δ=min{xa,bx}\delta=\min\{|x-a|,|b-x|\}, so xx is an interior point of R[a,b]\mathbb R\setminus[a,b].

Since we take arbitrary xR[a,b]x\in\mathbb R\setminus[a,b] , we obtain that every point of R[a,b]\mathbb R\setminus[a,b] is an interior point of R[a,b]\mathbb R\setminus[a,b] , so R[a,b]\mathbb R\setminus[a,b] is an open set. By the definition of closed set we have [a,b]=R(R[a,b])[a,b]=\mathbb R\setminus(\mathbb R\setminus[a,b]) is a closed set.


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