Q. Use Runge Kutta Fehlberg method with tolerance TOL=〖10〗^(-6), hmax=0.5, and hmin=0.05 to approximate the solutions to the following initial value problem. Compare the result to the actual value.
y^'=(t+〖2t〗^3)y^3-ty, 0≤t≤2,y(2)=1, y(0)=1/3 , actual solution y(t)=〖(3+2t^2+6e^(t^2 ))〗^(-1⁄2)
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Expert's answer
2018-05-17T11:51:36-0400
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