x3−5x+3=0
f(x)=x3−5x+3
f′(x)=3x2−5
xn+1=xn−f′(xn)f(xn) x0=−2
step12345x0−2.0000−2.7143−2.5140−2.4912−2.4909f(x0)5−3.4257−0.3187−0.0039−0.0000x1−2.7143−2.5140−2.4912−2.4909−2.4909f(x1)−3.4257−0.3187−0.00390.00000.0000
xI=−2.491
x0=1
step1234x01.00000.50000.64710.6566f(x0)−1.00000.62500.03560.0002x10.50000.64710.65660.6566f(x1)0.62500.03560.00020.0002
xII=0.657
x0=2
step1234x02.00001.85711.83481.8342f(x0)1.00000.11950.00280.0000x11.85711.83481.83421.8342f(x1)0.11950.00280.00000.0000
xIII=1.834
Comments