Given a function described as equation y = 3x + 4, what is y when x is 1, 2, and 3?
Consider the equation y=3x+4y=3x+4y=3x+4
Require to find yyy when x=1,2,3x=1,2,3x=1,2,3
Now x=1⇒y=3(1)+4=7x=1\Rightarrow y=3(1)+4=7x=1⇒y=3(1)+4=7
x=2⇒y=3(2)+4=10x=2\Rightarrow y=3(2)+4=10x=2⇒y=3(2)+4=10
x=3⇒y=3(3)+4=13x=3\Rightarrow y=3(3)+4=13x=3⇒y=3(3)+4=13
Therefore, the values of yyy are: y=7,10,13y=7,10,13y=7,10,13
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