Question

If for a sample of size 36, the standard error of mean is 4, then the population variance will be:

Answer 1

Given,

Size of the sample = 36

Standard error of mean = 4

Population variance $(\sigma^2)=(x-\mu)^2$

Now, substituting the values,

$\sigma^2= (36-4)^2$

$=32^2$

$=1024$