If for a sample of size 36, the standard error of mean is 4, then the population variance will be:
Given,
Size of the sample = 36
Standard error of mean = 4
Population variance (σ2)=(x−μ)2(\sigma^2)=(x-\mu)^2(σ2)=(x−μ)2
Now, substituting the values,
σ2=(36−4)2\sigma^2= (36-4)^2σ2=(36−4)2
=322=32^2=322
=1024=1024=1024
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment