Answer to Question #162636 in Quantitative Methods for Sunny

Question

social class VS. number of children in the family is tabulated below: find the probabilities.

No of children lower middle upper

0 7 18 6

1 9 38 23

2 34 97 58

3 37 31 30

1. P ( 3 children)
2. P ( Lower or 2 children)
3. P ( Middle and 1 child)
4. P ( lower / 2 children)
5. P ( 0 child / Middle)

Answer 1

1.Total number of families:

$N=7+18+6+9+38+23+34+97+58+37+31+30=392$

P ( 3 children)$=\frac{37+31+31}{392}=0.25$

2.

P ( Lower or 2 children)$=\frac{7+9+34+37+97+58}{392}=0.62$

3.

P ( Middle and 1 child)$=38/392=0.097$

4.

P ( lower / 2 children)$=\frac{7+9+37}{392}=0.135$

5.

P ( 0 child / Middle)$=\frac{7+6}{392}=0.033$