Question

In a weightlifting competition, the amount that the competitors can lift is normally distributed with mean = 196 kg and standard deviation = 11 kg. only the top 20% of all competitors will be able to advance to the next phase of the competition. What amount must a competitor lift in order to move into the next phase of the competition?

Answer 1

Given,

The mean lifted weight $(w) =196 kg$

Standard deviation $=11kg$

The competitors would have =(100-20)=80%

The z-score at 80 percentile (z)=0.84

$0.84=\frac{x-196}{11}$

$\Rightarrow 11\times0.84=x-196$

$x=205.26kg$