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Solve the following linear programming graphically [5] Minimize: 𝑧 = 200đ‘„ + 500𝑩 Subject to the constraints: đ‘„ + 2𝑩 ≄ 10 3đ‘„ + 4𝑩 ≀ 24 đ‘„ ≄ 0; 𝑩 ≄ 


Liala and Vinay both have to travel to various locations for advertising their company's products. The company reimburses their expenses such as accommodation, food etc. The company also blacklists an employee whenever the employee's expenditure in a given month exceeds â‚č 12000. The accounts department fits the data of monthly expenditure to the polynomial E_l(x) and E_v(x) (in â‚č ) for Liala and Vinay respectively, where x is the number of months since they joined the company (i.e., x = 1 represents the completion of one month). The polynomial fit is known to be applicable for a period of 35 months (i.e., x≀35). If E_l(x) - 12,000 = b(x-5.3)(x-11)(x-24), ~b>0 and E_v(x) - 12,000 = a(x-2.5)^2(x-5.3)(x-22), ~a>0. If Vinay and Liala have been blacklisted together for at least N times in 35 months, then find the value of N.



Liala and Vinay both have to travel to various locations for advertising their company's products. The company reimburses their expenses such as accommodation, food etc. The company also blacklists an employee whenever the employee's expenditure in a given month exceeds â‚č 12000. The accounts department fits the data of monthly expenditure to the polynomial E_l(x)

 and E_v(x) (in â‚č ) for Liala and Vinay respectively, where x

is the number of months since they joined the company (i.e., x = 1 represents the completion of one month). The polynomial fit is known to be applicable for a period of 34 months (i.e. x≀34). If E_l(x) - 12,000 = b(x-5.0)(x-11)(x-24), ~b>0  and E_v(x) - 12,000 = a(x-2.2)^2(x-5.0)(x-25), ~a>0. If Vinay and Liala have been blacklisted together for atleast N times in 34 months, then find the value of N



Sketch the graph of f(x)=2 log1/3 (x+4)−1 using transformation techniques. 


Given a Vmax of 7.45V and a modulation index of 0.691, calculate for Vmin. (5 points)



A manufacturing company produces a product from one raw material using a process A.

This process generates total solid wastes WA (in tonne) represented as

WA​(r)=1/15000​(−2r3+10r2+400r) where r is the amount of raw material used in tonne and 

r∈(0,10). If the company uses a different process B to produce the same product from same raw material, then the total solid waste generated is WB (in tonne) represented as W_B(r) = 1/10000(-2.2r3+11r2+440r). The company spends â‚č5,000in waste treatment using the process A by consuming 1 tonne of raw material. How much extra amount will the company have to pay in waste treatment for consuming 1 tonne of raw material if it uses the process B?




Given a Vmax of 7.45V and a modulation index of 0.691, calculate for Vmin

Let
A=2x^2i−3yzj+xz^2k
and
ϕ=2z−x^3y
, find
AĂ—â–œÏ•
at point (1,-1,1).

The temperature of a particular country

n

 is the number of the month, starting at n

=


n=0

 for January. The temperature in the country is greater than 40 o

C

oC

 for months Jun, July, August, and September. It is less than 40 o

C

oC

 for months January, February, March, April, November and December, and 40 o

C

oC

 for months May and October. If a

a

 is a positive integer, then which of the following options might be correct

T

(

n

)

=

a

(

n

−

4

)

(

n

−

9

)

−

40

T(n)=a(n−4)(n−9)−40

 T

(

n

)

=

a

(

4

−

n

)

(

n

−

9

)

−

40

T(n)=a(4−n)(n−9)−40

 T

(

n

)

=

a

(

4

−

n

)

(

9

−

n

)

+

40

T(n)=a(4−n)(9−n)+40

 T

(

n

)

=

a

(

4

−

n

)

(

n

−

9

)

+

40

T(n)=a(4−n)(n−9)+40

 The temperature in December is 40

−

14

a

40−14a

.

 The temperature in April is 40

−

3

a

40−3a

.


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