Question #75223

find the minimum number of intervals required to evaluate integartion 0 to 1 e^-x^2 dx woth an accuracy of 1/2 X 10^-4 by using trapezoidal rule

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Question #75223, Math / Other

find the minimum number of intervals required to evaluate integration 0 to 1ex21\mathrm{e}^{\wedge} - \mathrm{x}^{\wedge}2 dx with an accuracy of 1/2×1041 / 2 \times 10^{\wedge} - 4 by using trapezoidal rule

Answer.


ε(ba)312N2maxaxbf(x).| \varepsilon | \leq \frac {(b - a) ^ {3}}{12N^{2}} \max _ {a \leq x \leq b} f ^ {\prime \prime} (x).a=0,b=1.a = 0, b = 1.f(x)=ex2,f(x)=2xex2,f(x)=(4x22)ex2.f (x) = e ^ {- x ^ {2}}, f ^ {\prime} (x) = - 2 x e ^ {- x ^ {2}}, f ^ {\prime \prime} (x) = (4 x ^ {2} - 2) e ^ {- x ^ {2}}.max0x1f(x)=f(1)=2e0.7358.\max _ {0 \leq x \leq 1} f ^ {\prime \prime} (x) = f ^ {\prime \prime} (1) = \frac {2}{e} \approx 0.7358.So, 0.5×1040.735812N2N0.735812÷0.5×10435.\text{So, } 0.5 \times 10^{-4} \leq \frac{0.7358}{12N^{2}} \rightarrow N \geq \sqrt{\frac{0.7358}{12 \div 0.5 \times 10^{-4}}} \approx 35.


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