Question #56224

(b) Determine the optimal solution to the transportation problem given below using least cost method(10 marks)
V W X Y Z SUPPLY
A 1 9 13 36 51 50
B 24 12 16 20 1 100
C 14 33 1 23 26 150
DEMAND 100 70 50 40 40

Expert's answer

Answer on Question #56224 – Math – Other

(b) Determine the optimal solution to the transportation problem given below using least cost method (10 marks)


Solution


Cells (A,V) and (C,X) and (B,Z) both have 1 cost so we arbitrarily choose the second and assign

x33=50x_{33} = 50. Cross out column 3. The amount left in row 3 is 15050=100150 - 50 = 100.

x25=40x_{25} = 40. Cross out column 5. The amount left in row 2 is 10040=60100 - 40 = 60.

x11=50x_{11} = 50. Cross out row 1. The amount left in column 1 10050=50100 - 50 = 50.

x22=60x_{22} = 60. Cross out row 2. The amount left in column 2 7060=1070 - 60 = 10.

Therefore,


x32=10;x31=50;x34=100(50+10)=40.x_{32} = 10; x_{31} = 50; x_{34} = 100 - (50 + 10) = 40.


Number of basic variables is 3+51=73 + 5 - 1 = 7.

The final table:



The total transportation cost associated with this solution is


501+6012+401+5014+1033+501+4023=2810.50 \cdot 1 + 60 \cdot 12 + 40 \cdot 1 + 50 \cdot 14 + 10 \cdot 33 + 50 \cdot 1 + 40 \cdot 23 = 2810.


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