Question #52770

The position vectors of the points A and B are (1,5,3) and (3,6,6). Find the vector equation of the line AB and the points where the line intersects the coordinate planes.

Expert's answer

Answer on Question #52770, Math, Other

Task: The position vectors of the points A and B are (1,5,3) and (3,6,6). Find the vector equation of the line AB and the points where the line intersects the coordinate planes.

Answer:

Find a direction vector.


m=OBOA=[3,6,6][1,5,3]=[2,1,3]\vec {m} = O \vec {B} - O \vec {A} = [ 3, 6, 6 ] - [ 1, 5, 3 ] = [ 2, 1, 3 ]


the vector equation of the line AB is [x,y,z]=[1,5,3]+t[2,1,3][x,y,z] = [1,5,3] + t\cdot [2,1,3]

so x=1+2tx = 1 + 2t ; y=5+ty = 5 + t ; z=3+3tz = 3 + 3t .

for the x-z plane, y=0y = 0 , so 5+t=05 + t = 0 , meaning that t=5t = -5 . So We get (9,0,12)(-9,0,-12) .

for the x-y plane, z=0z = 0 , so 3+3t=03 + 3t = 0 , meaning that t=1t = -1 . So We get (1,4,0)(-1,4,0) .

for the y-z plane, x=0x = 0 , so 1+2t=01 + 2t = 0 , meaning that t=1/2t = -1/2 . So We get (0,9/2,3/2)(0,9/2,3/2) .

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