Question #45216

if x and b are complementary angles such that cos x=square root of 3/2.Find the value of 2 sin b sin x

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Answer on Question #45216 – Math – Other

if x and b are complementary angles such that cos(x)=32\cos(x) = \frac{\sqrt{3}}{2}. Find the value of 2 sin b sin x

Solution

If cos(x)=32\cos(x) = \frac{\sqrt{3}}{2}, then x=30x = 30{}^\circ or pi/6.

Two angles are complementary when they add up to 9090{}^\circ, i.e. x+b=90x + b = 90{}^\circ.

Knowing that b and x are complementary, we can find that b=90x=90x=60b = 90{}^\circ - x = 90{}^\circ - x = 60{}^\circ or pi/3.

Recall sinb=sin60=32\sin b = \sin 60{}^\circ = \frac{\sqrt{3}}{2}, sinx=sin30=12\sin x = \sin 30{}^\circ = \frac{1}{2}.

Then 2sinbsinx=23212=322 \sin b \sin x = 2 \cdot \frac{\sqrt{3}}{2} \cdot \frac{1}{2} = \frac{\sqrt{3}}{2}.


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