Question #43143

A tradesman marks an article Rs 205 above the cost price. He allows a discount of 10% on the marked price. Find his profit %, if the cost price is x?

Expert's answer

Answer on Question #43143-Math-Other

A tradesman marks an article Rs 205 above the cost price. He allows a discount of 10% on the marked price. Find his profit %, if the cost price is x?

Solution

The cost price is


C.P.=Rsx.C. P. = R s x.


The marked price is


M.P.=C.P.+Rs205=Rs(205+x).M. P. = C. P. + R s 205 = R s (205 + x).


Selling price (S.P.) is


S.P.=(100discount)M. P.100=(10010)M. P.100=Rs0.9(205+x).S. P. = \frac{(100 - \text{discount}) \cdot \text{M. P.}}{100} = \frac{(100 - 10) \cdot \text{M. P.}}{100} = R s 0.9(205 + x).Profit %=S. P. - C. P.C.P.100=Rs 0.9(205+x)RsxRs x100=(18450x10)%.\text{Profit \%} = \frac{\text{S. P. - C. P.}}{C. P.} 100 = \frac{\text{Rs 0.9}(205 + x) - R s x}{\text{Rs x}} 100 = \left(\frac{18450}{x} - 10\right)\%.


Answer: (18450x10)%\left(\frac{18450}{x} - 10\right)\%

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