Question #42059
Condition.
Solution.
Cost of program=cost+admin fee+20*(HR staff needed)*(hours to complete training)+n*12.5*(hours to complete training)
n- new employees
we can get system of equations:
Where
- new employees for each program
C - cost of each program
when
Answer.
As start cost of program A is less than cost of program D for case if no new employees as program A is more cost efficiently than program D.
And also, it is more cost efficiently than programs B,C (they have negative values of number of new employees).
So, program A is the most cost efficiently (answer A)).
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Comments
Dear Steeeee. Thank you for your comments. In this question we used the following calculations: A is 14000+145+(3x20x25)+(12.5x25)x10 = 14000+145+1500+3125=18770, B is 13000+170+(4x20x28)+(12.5x28)x10= 13000+170+2240+3500=18910. Therefore program A is more cheaper than program B.
your answer is wrong The answer is B Answer A is 14000+145+(3x20x25)+(12.5x25) = 14000+145+1500+312.50= 15957.50 Answer B is 13000+170+(4x20x28)+(12.5x28)= 13000+170+2240+350 = 15760 Answer B is correct
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I have liked the answer - Thanks once again. Zainab
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