Answer on Question#38639 – Math – Other
Using the pumping lemma for regular languages we can write a regular expression for {w∣w in {0,1}∗ and w does not have three consecutive 0′s}\{w|w \text{ in } \{0,1\}^* \text{ and } w \text{ does not have three consecutive } 0's\}{w∣w in {0,1}∗ and w does not have three consecutive 0′s}. So our language is regular.
Answer: A.
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