Question #33879

Given that A × B=O, B × C=O, and A≠0, B≠0, C≠0. Find the value of A × C

Expert's answer

Task. Given that A×B=OA\times B=O, B×C=OB\times C=O, and A0A\neq 0, B0B\neq 0, C0C\neq 0. Find the value of A×CA\times C.

Solution. Recall that for any two vectors AA and BB in R3\mathbb{R}^{3} the absolute value of their cross product A×B|A\times B| is equal to

A×B=ABsinAB^,|A\times B|=|A|\cdot|B|\cdot\sin\widehat{AB},

where AB^\widehat{AB} is the angle between vectors AA and BB.

By assumption A0|A|\neq 0, B0|B|\neq 0, C0|C|\neq 0, and

ABsinAB^=0,BCsinCB^=0.|A|\cdot|B|\cdot\sin\widehat{AB}=0,\qquad|B|\cdot|C|\cdot\sin\widehat{CB}=0.

Therefore

sinAB^=sinBC^=0.\sin\widehat{AB}=\sin\widehat{BC}=0.

This means that vectors AA and BB are collinear, and similarly BB and CC are also collinear. Hence, AA and CC are also collinear, and so

sinAC^=0.\sin\widehat{AC}=0.

Therefore

A×C=ACsinAC^=0,|A\times C|=|A|\cdot|C|\cdot\sin\widehat{AC}=0,

which means that A×C=0A\times C=0.

Answer. A×C=0A\times C=0.

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