Answer to Question #334065 in Math for Agl

Question #334065

A person walks 750m due north, then 250m due east. If the entire walk


takes 13 minutes, find the person's average velocity?



An object moves along a straight line. First it travels at a velocity of


12m/s for 6s and then continues at the same direction with 20m/s for 3s.


What is its average speed?



For 10s, the velocity of a car which travels with a constant acceleration,


changes from 10m/s to 20m/s. How far does the car travel?



A cyclist covers a distance of 15 miles in 2 hours. Calculate his speed.



A boy walks at a speed of 4 kmph. How much time does he take to walk a


distance of 20 km?



A car takes 4 hours to cover a distance, if it travels at a speed of 40 mph. What should be its speed to cover the same distance in 1.5 hours?



If a person drives his car in the speed 50 miles per hour, how far can he


cover in 90 minutes?

1
Expert's answer
2022-04-27T16:32:29-0400

a.


vave=750m+250m13min=100013m/minv_{ave}=\dfrac{750m+250m}{13min}=\dfrac{1000}{13}m/min

b.


vave=12m/s(6s)+20m/s(3s)6s+3s=443m/sv_{ave}=\dfrac{12m/s(6s)+20m/s(3s)}{6s+3s}=\dfrac{44}{3}m/s

c.


v1=v0+at1=>a=v1v0t1v_1=v_0+at_1=>a=\dfrac{v_1-v_0}{t_1}

s1=v0t1+at122s_1=v_0t_1+\dfrac{at_1^2}{2}

s1=v0t1+(v1v0)t12s_1=v_0t_1+\dfrac{(v_1-v_0)t_1}{2}

s1=(v1+v0)t12s_1=\dfrac{(v_1+v_0)t_1}{2}

s1=(20m/s+10m/s)10s2=150ms_1=\dfrac{(20m/s+10m/s)10s}{2}=150m

d.


v=15mi/2h=7.5 mi/hv=15mi/2h=7.5\ mi/h

e.


t=20km4km/h=5hourst=\dfrac{20km}{4km/h}=5hours

f.


v=40mi/h(4h)1.5h=3203mi/hv=\dfrac{40mi/h(4h)}{1.5h}=\dfrac{320}{3}mi/h

3203\dfrac{320}{3} mph


g. 90min=1.5h90min=1.5h


50mi/h(1.5h)=75mi50mi/h(1.5h)=75mi

75 miles


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