A ball kicked horizontally at 10.0m/s from a cliff 80m high. How far from the base of the cliff will the stone strike the ground?
h(t)=H−gt22=80−4.9t2h(t)=H-\frac{gt^2}{2}=80-4.9t^2h(t)=H−2gt2=80−4.9t2
h(t)=0→80−4.9t2→t=804.9=4.04s.h(t)=0 \to 80-4.9t^2 \to t=\sqrt{\frac{80}{4.9}}=4.04 s.h(t)=0→80−4.9t2→t=4.980=4.04s.
S=vt=10∗4.04=40.4m.S=vt=10*4.04=40.4m.S=vt=10∗4.04=40.4m.
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