Question #328609

A ball kicked horizontally at 10.0m/s from a cliff 80m high. How far from the base of the cliff will the stone strike the ground?


1
Expert's answer
2022-04-14T17:00:56-0400

h(t)=Hgt22=804.9t2h(t)=H-\frac{gt^2}{2}=80-4.9t^2

h(t)=0804.9t2t=804.9=4.04s.h(t)=0 \to 80-4.9t^2 \to t=\sqrt{\frac{80}{4.9}}=4.04 s.

S=vt=104.04=40.4m.S=vt=10*4.04=40.4m.


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