Derive the Cardano-Tartaglia formula x=n2+(n2)2+(m3)33−−n2+(n2)2+(m3)33x= \sqrt[3]{\frac{n}{2}+\sqrt{(\frac{n}{2})^2+(\frac{m}{3})^3}} - \sqrt[3]{\frac{-n}{2}+\sqrt{(\frac{n}{2})^2+(\frac{m}{3})^3}}x=32n+(2n)2+(3m)3−32−n+(2n)2+(3m)3 for solving cubic x3+mx=n
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