Answer to Question #257726 in Math for Mohammed

Question #257726

A particle is subject to uniform gravity and the linear resistance force -mKv, where K is a positive constant and v is the velocity of the particle. Initially the particle is projected with speed "\\mu" in a direction making an angle "\\alpha" with the horizontal.

(a). Find the vector equation of motion and the corresponding scalar equations of motion.

(b). Show that the solution for the trajectory of the particle at t=0,z=0,x=0 is x="\\mu"cos"\\alpha" /K (1-e-Kt) z=K"\\mu"sin"\\alpha"+g/K2 (1-e-Kt)-g/K t

(c). Find an approximate formula for the range on level ground when the resistance parameter "\\lambda"=K"\\mu"/g is small.


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