Continue the two sequences of numbers below and find an equation to each of the sequences:
n 1 2 3 4 5 6 7 Equation
an 2 5 9 14 20 27
bn 1 3 12 60 360 2520
an=an−1+n+1,n≥2,a1=1
a2=a1+2+1=2+3=5
a3=a2+3+1=5+4=9
a4=a3+4+1=9+5=14
a5=a4+5+1=14+6=20
a6=a5+6+1=20+7=27
a7=a6+7+1=5+4=27+8=35
bn=bn−1(n+1),n≥2,b1=1
b2=b1(2+1)=3
b3=b2(3+1)=12
b4=b3(4+1)=60
b5=b4(5+1)=360
b6=b5(6+1)=2520
b7=b6(7+1)=20160
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