2021-10-16T13:10:37-04:00 
                    
                
        
            Continue the two sequences of numbers below and find an equation to each of the sequences:
        1 
                    
                            
                                        2021-10-19T15:59:02-0400
                    
                                                    
                                a n = a n − 1 + n + 1 , n ≥ 2 , a 1 = 1 a_n=a_{n-1}+n+1, n\geq2, a_1=1 a n  = a n − 1  + n + 1 , n ≥ 2 , a 1  = 1  
a 2 = a 1 + 2 + 1 = 2 + 3 = 5 a_2=a_1+2+1=2+3=5 a 2  = a 1  + 2 + 1 = 2 + 3 = 5  
a 3 = a 2 + 3 + 1 = 5 + 4 = 9 a_3=a_2+3+1=5+4=9 a 3  = a 2  + 3 + 1 = 5 + 4 = 9  
a 4 = a 3 + 4 + 1 = 9 + 5 = 14 a_4=a_3+4+1=9+5=14 a 4  = a 3  + 4 + 1 = 9 + 5 = 14  
a 5 = a 4 + 5 + 1 = 14 + 6 = 20 a_5=a_4+5+1=14+6=20 a 5  = a 4  + 5 + 1 = 14 + 6 = 20  
a 6 = a 5 + 6 + 1 = 20 + 7 = 27 a_6=a_5+6+1=20+7=27 a 6  = a 5  + 6 + 1 = 20 + 7 = 27  
a 7 = a 6 + 7 + 1 = 5 + 4 = 27 + 8 = 35 a_7=a_6+7+1=5+4=27+8=35 a 7  = a 6  + 7 + 1 = 5 + 4 = 27 + 8 = 35  
b n = b n − 1 ( n + 1 ) , n ≥ 2 , b 1 = 1 b_n=b_{n-1}(n+1), n\geq2, b_1=1 b n  = b n − 1  ( n + 1 ) , n ≥ 2 , b 1  = 1  
b 2 = b 1 ( 2 + 1 ) = 3 b_2=b_1(2+1)=3 b 2  = b 1  ( 2 + 1 ) = 3  
b 3 = b 2 ( 3 + 1 ) = 12 b_3=b_2(3+1)=12 b 3  = b 2  ( 3 + 1 ) = 12  
b 4 = b 3 ( 4 + 1 ) = 60 b_4=b_3(4+1)=60 b 4  = b 3  ( 4 + 1 ) = 60  
b 5 = b 4 ( 5 + 1 ) = 360 b_5=b_4(5+1)=360 b 5  = b 4  ( 5 + 1 ) = 360  
b 6 = b 5 ( 6 + 1 ) = 2520 b_6=b_5(6+1)=2520 b 6  = b 5  ( 6 + 1 ) = 2520  
b 7 = b 6 ( 7 + 1 ) = 20160 b_7=b_6(7+1)=20160 b 7  = b 6  ( 7 + 1 ) = 20160  
 
                                                 
                 
                    
        
            
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