Answer to Question #244710 in Math for ivan

Question

Given a V_max of 7.45V and a modulation index of 0.691, calculate for V_min

Answer 1

$$m=\dfrac{V_{max}-V_{min}}{V_{max}+V_{min}}$$

$$m(V_{max}+V_{min})=V_{max}-V_{min}$$

$$V_{min}=\dfrac{1-m}{1+m}V_{max}$$

$$V_{min}=\dfrac{1-0.691}{1+0.691}(7.45\ V)=1.36\ V$$

$$V_{min}=1.36\ V$$