Answer to Question #236238 in Math for luka

Question #236238

The curve y = aX^3– 2X^2– X + 7 has a gradient of 3 at the point where X =3.

Determine the value of a.

Expert's answer

Gradient: "y'(x)=3ax^2-4x-1."

"y'(3)=3\\to3a*3^2-4*3-1=3\\to27a=16\\to a=\\frac{16}{27}."

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