Question #233092

L {t2 cos t}


1
Expert's answer
2021-09-06T16:18:26-0400

L[t2cost]=(1)2d2ds2L[cost]=d2ds2(ss2+1)=2s(s23)(s2+1)3.L[t^2cos t]=(-1)^2\frac{d^2}{ds^2}L[cost]=\frac{d^2}{ds^2}(\frac{s}{s^2+1})=\frac{2s(s^2-3)}{(s^2+1)^3}.


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