Answer to Question #233091 in Math for abi

Question #233091

L{ e^2t(t-1)²}

Expert's answer

"L[e^{2t}(t-1)^2]=L[e^{2t}(t^2-2t+1)]=\\frac{(s-2)^2-2(s-2)+2}{(s-2)^3}=\\frac{s^2-6s+10}{(s-2)^3}."

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