Answer to Question #233091 in Math for abi

Question

L{ e^2t (t-1)² }

Answer 1

$L[e^{2t}(t-1)^2]=L[e^{2t}(t^2-2t+1)]=\frac{(s-2)^2-2(s-2)+2}{(s-2)^3}=\frac{s^2-6s+10}{(s-2)^3}.$