L{ e2t (t-1)2 }
L[e2t(t−1)2]=L[e2t(t2−2t+1)]=(s−2)2−2(s−2)+2(s−2)3=s2−6s+10(s−2)3.L[e^{2t}(t-1)^2]=L[e^{2t}(t^2-2t+1)]=\frac{(s-2)^2-2(s-2)+2}{(s-2)^3}=\frac{s^2-6s+10}{(s-2)^3}.L[e2t(t−1)2]=L[e2t(t2−2t+1)]=(s−2)3(s−2)2−2(s−2)+2=(s−2)3s2−6s+10.
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