Answer to Question #233090 in Math for abi

Question

L^-1{ s / (s²+1)² }

Answer 1

$L^{-1}[\frac{s}{(s^2+1)^2}]=\frac{d}{dt}L^{-1}[\frac{1}{(s^2+1)^2}]=$

$\frac{d}{dt}[\frac{1}{2}sin(t)-\frac{1}{2}tcos(t)]=\frac{1}{2}tsin(t).$