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Question #232314
L{ s/ (s
2
+1)
2
}
Expert's answer
f
(
t
)
=
L
−
1
(
s
(
s
2
+
1
)
2
)
=
1
2
L
−
1
(
2
(
1
)
s
(
s
2
+
(
1
)
2
)
2
)
f(t)=L^{-1}\big(\dfrac{s}{(s^2+1)^2}\big)=\dfrac{1}{2}L^{-1}\big(\dfrac{2(1)s}{(s^2+(1)^2)^2}\big)
f
(
t
)
=
L
−
1
(
(
s
2
+
1
)
2
s
)
=
2
1
L
−
1
(
(
s
2
+
(
1
)
2
)
2
2
(
1
)
s
)
=
1
2
t
sin
t
=\dfrac{1}{2}t\sin t
=
2
1
t
sin
t
f
(
t
)
=
L
−
1
(
s
(
s
2
+
1
)
2
)
=
1
2
t
sin
t
f(t)=L^{-1}\big(\dfrac{s}{(s^2+1)^2}\big)=\dfrac{1}{2}t\sin t
f
(
t
)
=
L
−
1
(
(
s
2
+
1
)
2
s
)
=
2
1
t
sin
t
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on Dec 2023
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