Answer to Question #232297 in Math for abi

Question

L{e^2s/s^3)

Answer 1

$$L^{-1}\{\dfrac{e^{2s}}{s^3}\}=H(t-(-2))L^{-1}\{\dfrac{1}{s^3}\}(t-(-2))$$

$$=H(t+2)\cdot\dfrac{(t+2)^2}{2}$$

$$L^{-1}\{\dfrac{e^{2s}}{s^3}\}=\dfrac{H(t+2)\cdot(t+2)^2}{2}$$