Question #218259

X=y/bcqrX=y/bc-√qr


Find the value of r when b=2,c=1,q=3,x=2 and y= 4


1
Expert's answer
2021-07-19T05:51:03-0400
qr=ybcx\sqrt{qr}=\dfrac{y}{bc}-x

r=(ybcx)2qr=\dfrac{(\dfrac{y}{bc}-x)^2}{q}

Substitute


r=(42(1)2)23r=\dfrac{(\dfrac{4}{2(1)}-2)^2}{3}

r=0r=0


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