Calculate the area of a trapezium that has parallel sides of 10cm and 6cm respectively and the perpendicular distance of 7 cm between the parallel sides.
A=a+b2h=10+62∗7=56cm2.A=\frac{a+b}{2}h=\frac{10+6}{2}*7=56 cm^2.A=2a+bh=210+6∗7=56cm2.
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