Answer in Math for Mike #216728

Question #216728

(2t-4)² i + 3t j - t²k

Expert's answer

Answer:-

$(2t-4)^2 i + 3t j - t^2 k$

= $(4t^2+16-16t)i+3tj-t^2k$

= $(4i-k)t^2+(-16i+3j)t+(16i)$

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