Question #214801

find : L inverse [1 divided by (s+1)(s

Expert's answer

L−1(1(s+1)s)=L(1s−1s+1)=1−e−tL^{-1}(\dfrac{1}{(s+1)s})=L(\dfrac{1}{s}-\dfrac{1}{s+1})=1-e^{-t}


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