Answer to Question #214801 in Math for jannathul prudous
find : L inverse [1 divided by (s+1)(s
1
2021-07-16T03:30:14-0400
"L^{-1}(\\dfrac{1}{(s+1)s})=L(\\dfrac{1}{s}-\\dfrac{1}{s+1})=1-e^{-t}"
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