Question #206633
A car move at a constant velocity of 20m/s for 10seconds and then accelerated uniformly to a velocity of 30m/s over 15 seconds. Calculate the distance covered during the motion
1
Expert's answer
2021-06-14T16:17:09-0400
s1=v1t1s_1=v_1t_1

s1=20 m/s10s=200 ms_1=20\ m/s\cdot 10s=200\ m

v2=v1+at2v_2=v_1+at_2

a=v2v1t2a=\dfrac{v_2-v_1}{t_2}

s2=v1t2+at222=v1t2+(v2v1)t22s_2=v_1t_2+\dfrac{at_2^2}{2}=v_1 t_2+\dfrac{(v_2-v_1)t_2}{2}

s2=20 m/s15 s+(30 m/s20 m/s)15 s2=375 ms_2=20 \ m/s\cdot15\ s+\dfrac{(30 \ m/s-20 \ m/s)15\ s}{2}=375\ m


s=s1+s2s=s_1+s_2

s=200 m+375 m=575 ms=200\ m+375\ m=575\ m

The distance covered during the motion is 575 metres.



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