A piece of lead falls from a height of 100 meters on a fixed non _ conducting slad which brings it to rest. Show that it is temperature immediately 7.5°c, knowing that the specific heat of lead is 0.13 J/g°c.)
When the lead ball falls on the non-conducting surface, the lost potential energy is absorbed by the ball as heat energy.
Potential energy of lead "=" thermal energy of slab
"\\varDelta T=\\dfrac{gh}{C}"
Given "g=9.8\\ m\/s^{2}, h=100\\ m,"
"C=0.13\\ J\/(g \\degree C)=130\\ J\/(kg \\degree C)"
Substitute
"\\varDelta T=7.5\\ \\degree C"
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