Question

Integrate the following

A) 3x + 21x²

B) x³-1

 ∫³₂ -------- dx

x²

Answer 1

A) $\int(3x+21x^2)dx=\frac{3}{2}x^2+7x^3+C.$

B) $\int_{2}^3\frac{x^3-1}{x^2}dx=\int_{2}^3(x-x^{-2})dx=(\frac{1}{2}x^2+\frac{1}{x})|_{x=2}^{x=3}=\frac{7}{3}.$