Question #156407

Using Data Below, Compute for the following. Show the Correct and Complete solution

a. Mean

b. Median

c. Mode

d. Standard Deviation

21, 27, 28, 20, 18, 18, 19, 17, 22, 24, 23, 27, 26, 25, 26, 25, 22, 21, 22, 26, 28, 26, 20, 19, 17,18, 26, 27, 27, 22, 23, 25, 25, 27, 28, 20, 19, 17, 16,16, 20,16, 21, 26, 27, 26, 28,16, 25, 28


Expert's answer

16,16,16,16,17,17,17,18,18,18,19,19,19,16, 16, 16, 16, 17, 17, 17, 18, 18, 18, 19, 19, 19,

20,20,20,20,21,21,21,22,22,22,22,23,23,20, 20, 20, 20, 21, 21, 21, 22, 22, 22, 22, 23, 23,

24,25,25,25,25,25,26,26,26,26,26,26,26,24, 25, 25, 25, 25, 25, 26, 26, 26, 26, 26, 26, 26,

27,27,27,27,27,27,28,28,28,28,2827, 27, 27, 27, 27, 27, 28, 28, 28, 28, 28


a.

Mean=150(16(4)+17(3)+18(3)+19(3)Mean=\dfrac{1}{50}\big(16(4)+17(3)+18(3)+19(3)

+20(4)+21(3)+22(4)+23(2)+24+25(5)+20(4)+21(3)+22(4)+23(2)+24+25(5)

+26(7)+27(6)+28(5))=113650=22.72+26(7)+27(6)+28(5)\big)=\dfrac{1136}{50}=22.72



b.

Median=23+232=2Median=\dfrac{23+23}{2}=2

c.

Mode=26,appeared 7 timesMode=26, \text{appeared 7 times}

d.

s2=i=1n(xixˉ)2n1s^2=\dfrac{\displaystyle\sum_{i=1}^n(x_i-\bar{x})^2}{n-1}


i=150(xixˉ)2\displaystyle\sum_{i=1}^{50}(x_i-\bar{x})^2

=(1622.72)2(4)+(1722.72)2(3)+(1822.72)2(3)=(16-22.72)^2(4)+(17-22.72)^2(3)+(18-22.72)^2(3)

+(1922.72)2(3)+(2022.72)2(4)+(2122.72)2(3)+(19-22.72)^2(3)+(20-22.72)^2(4)+(21-22.72)^2(3)

+(2222.72)2(4)+(2322.72)2(2)+(2422.72)2+(22-22.72)^2(4)+(23-22.72)^2(2)+(24-22.72)^2

+(2522.72)2(5)+(2622.72)2(7)+(2722.72)2(6)+(25-22.72)^2(5)+(26-22.72)^2(7)+(27-22.72)^2(6)

+(2822.72)2(5)=780.08+(28-22.72)^2(5)=780.08

s2=780.08501=15.92s^2=\dfrac{780.08}{50-1}=15.92


Standard deviation=s=s2=15.92=3.99Standard\ deviation=s=\sqrt{s^2}=\sqrt{15.92}=3.99


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