Question #143108
Determine the intensity of shear of an oil having viscosity = 1.2 poise and is used for lubrication in the clearance between a 10 cm diameter shaft and its journal bearing. The clearance is 1.0 mm and shaft rotates at 200 r.p.m.
1
Expert's answer
2020-11-10T20:01:54-0500

Given:

μ=1.2poise=0.12Ns/m2\mu=1.2poise=0.12N\cdot s/m^2

Diameter of shaft D=10cm=0.1mD=10cm=0.1m

Distance between shaft and journal bearing dy=1.0mm=103mdy=1.0mm=10^{-3}m

Speed of shaft N=200 r.p.m.N=200\ r.p.m.


Tangential speed of shaft is given by


u=πDN60=π0.1m200 r.p.m.60=π3m/su=\dfrac{\pi DN}{60}=\dfrac{\pi\cdot0.1m\cdot200\ r.p.m.}{60}=\dfrac{\pi}{3}m/s

Change of velocity between shaft and bearing


du=u0=π3m/sdu=u-0=\dfrac{\pi}{3}m/s

Mathematically


τ=μdudy=0.12Ns/m2×π3m/s103m=\tau=\mu\dfrac{du}{dy}=0.12N\cdot s/m^2\times\dfrac{\dfrac{\pi}{3}m/s}{10^{-3}m}=

=40πN/m2125.6637N/m2=40\pi N/m^2\approx125.6637 N/m^2


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