Question #10710
Simplify usinf identites:
186*186*186+14*14*14/186*186-186*14+14*14
186*186*186+14*14*14/186*186-186*14+14*14
Expert's answer
(186*186*186+14*14*14)/(186*186-186*14+14*14)
Let's recall that a3+b3=(a+b)(a2-ab+b2) . In the numerator we have sum of two cubes, in the denominator the second braces from the right part of mentioned formula. Therefore
(186*186*186+14*14*14)/(186*186-186*14+14*14)=(186+14)(186*186-186*14+14*14)/(186*186-186*14+14*14)= =186+14=200
Let's recall that a3+b3=(a+b)(a2-ab+b2) . In the numerator we have sum of two cubes, in the denominator the second braces from the right part of mentioned formula. Therefore
(186*186*186+14*14*14)/(186*186-186*14+14*14)=(186+14)(186*186-186*14+14*14)/(186*186-186*14+14*14)= =186+14=200
Learn more about our help with Assignments: Math
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
#339914 on Dec 2023
#339914 on Dec 2023
Comments