Let X be the random variable denoting the mark in the test scored by the students.
Given, μ=70,σ=10. Let z=σX−μ=10X−70
a. P(students score more than 80)=P(X>80)=P(σX−μ>1080−70)=P(z>1)=1−P(z<1)=1−0.8413(Using Normal distribution table)=0.1587
Therefore, 15.87% of students scored above 80 marks.
b.
P(students pass the test)=P(X≥60)=P(σX−μ≥1060−70)=P(z≥−1)=1−P(z<−1)=1−0.1587(Using Normal distribution table)=0.8413
Therefore, 84.13% of students passed in the test.
c.
P(students fail the test)=P(X<60)=P(σX−μ<1060−70)=P(z<−1)=0.1587(Using Normal distribution table)
Therefore, 15.87% of students failed in the test.
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