Question #297619

A petrol pump station has two pumps. The







service times follows the exponential







distribution with a mean of 4 minutes and







cars arrive for service in a Poisson process at







the rate 10 cars per hour. Find the







probability of that a customer has to wait for







service.

1
Expert's answer
2022-02-15T11:13:18-0500

 μ=604=15 per hour λ=10 per hour \begin{gathered} \mu=\frac{60}{4}=15 \text { per hour } \\ \lambda=10 \text { per hour } \end{gathered}

P(Customer has to wait for service is) =1μλ= \frac{1}{\mu-\lambda}

=11510=0.2\begin{aligned} &=\frac{1}{15-10} \\ &=0.2 \end{aligned}

Now proportion of time pumps remain idle.

So, it can be explained by formula λμ.\frac{\lambda}{\mu}.

 i.e. λμ=1015=0.66\text { i.e. } \frac{\lambda}{\mu}=\frac{10}{15}=0.66  


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