Question #267642

Solve using simplex method

z = 3000x + 5000y

2x + y <= 16

x + 2y <= 11

x + 3y <= 15


1
Expert's answer
2021-11-18T09:45:08-0500

Max z=3000x+5000yz=3000 x+5000 y subject to 2x+y16x+2y11 and x,y02 x+y \leq 16 x+2 y \leq 11\ and\ x, y \geq 0

The problem is converted to canonical form by adding slack, surplus and artificial variables as appropriate

1. As the constraint- 1 is of type ' \leq ' we should add slack variable S1S_{1}

2. As the constraint- 2 is of type ' \leq ' we should add slack variable S2S_{2}

After introducing slack variables

Maxz=3000x+5000y+0S1+0S2\operatorname{Max} z=3000 x+5000 y+0 S_{1}+0 S_{2}

subject to

 2x+y+S1=16x+2y+S2=11\begin{array}{rr} 2 x+y+S_{1} & =16 \\ x+2 y+S_{2} & =11 \end{array}

 

and x,y,S1,S20x, y, S_{1}, S_{2} \geq 0



Since all ZjCj0Zj-Cj≥0

Hence, optimal solution is arrived with value of variables as :

x=7,y=2x=7,y=2

Max z=31000z=31000


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