A firm makes two products A and B. It has a total production capacity of 9 tonnes per day, with A and B utilising the same production facilities. The firm has a permanent contract to supply at least 2 tonnes of A per day ti another company. Each tonne of A requires 20 machine hours of production time abd each tonne of B requires 50 machine hours of production time. The daily maximum possible number of machine hours is 360. All the firm's output can be sold and the profit made is $80 per tonne of A and $120 per tonne of B. To formulate the problem of maximising the profit as an LPP and to solve it graphically.
Let product A be x and product B be y. Therefore we have:
"x + y \\le9"
"x\\ge2, y\\ge3"
Each tonne of A requires 20 machine hours of production time and each tonne of B requires 50 machine hours of production time. The daily maximum possible number of machine hours is 360, thus:
"20x+50y\\le360"
All the firm's output can be sold and the profit made is $80 per tonne of A and $120 per tonne of B. Thus:
"Z=80x+120y" - maximize
"x + y \\le9"
"20x+50y\\le360"
"x\\ge2, y\\ge3"
solving for x and y we get x = 3, y = 6
Thus "Z=80x+120y=80\\cdot3+120\\cdot6=960"
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