Maximize Z=24−A−B−CZ=24-A-B-CZ=24−A−B−C
subject to,
A+B+C≤24B+C≥8A,B,C≥0A+B+C \le 24\\ B+C\ge8\\ A,B,C\ge0A+B+C≤24B+C≥8A,B,C≥0
for simplex calculation,
Maximize Z=24−A−B−C+0S1+0S2−MA1Z=24-A-B-C+0S_1+0S_2-MA_1Z=24−A−B−C+0S1+0S2−MA1
A+B+C+S1=24B+C−S2+A1=8A,B,C,S1,S2,A1≥0A+B+C+S_1 = 24\\ B+C-S_2+A_1=8\\ A,B,C,S_1,S_2,A_1\ge0A+B+C+S1=24B+C−S2+A1=8A,B,C,S1,S2,A1≥0
iteration 1
iteration 2
answer is ,
A=0,B=8,C=0Zmax=24−0−8−0=16Zmax=16\bold{A=0,B=8,C=0}\\ Z_{max}=24-0-8-0=16\\ \bold{Z_{max}=16}A=0,B=8,C=0Zmax=24−0−8−0=16Zmax=16
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