x1+x2≥6x_1+x_2\geq 6x1+x2≥6
3x1+2x2≤303x_1+2x_2\leq 303x1+2x2≤30
2x1+x2≤52x_1+x_2\leq 52x1+x2≤5
x1,x2≥0x_1, x_2\geq 0x1,x2≥0
Maximize z=5x1+8x2z=5x_1+8x_2z=5x1+8x2
Green region shows all solutions of {x1+x2≥63x1+2x2≤302x1+x2≤5\begin{cases} x_1+x_2\geq 6 \\3x_1+2x_2\leq 30 \\ 2x_1+x_2\leq 5 \end{cases}⎩⎨⎧x1+x2≥63x1+2x2≤302x1+x2≤5
And red region shows all solutions of x1,x2≥0x_1,x_2\geq 0x1,x2≥0
We can see that there is no solution of the system {x1+x2≥63x1+2x2≤302x1+x2≤5x1,x2≥0\begin{cases} x_1+x_2\geq 6 \\3x_1+2x_2\leq 30 \\ 2x_1+x_2\leq 5 \\ x_1,x_2\geq 0 \end{cases}⎩⎨⎧x1+x2≥63x1+2x2≤302x1+x2≤5x1,x2≥0 because intersection of these regions is empty.
Therefore, we can’t maximize z=5x1+8x2z=5x_1+8x_2z=5x1+8x2 because there is no (x1,x2)(x_1,x_2)(x1,x2) , for which all inequalities are satisfied.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments