Question #34412

Mr. X went to market to purchase 3 kg of sugar, 10 kg of wheat and 1kg of salt. In a shop, ARPICO near to Mr. X’s residence, these commodities are priced at Rs 20, Rs10 and Rs 8 per kg whereas in the local market, CARGILLS these commodities are priced at Rs 15, Rs. 8 and Rs 6 per kg respectively. If the cost of traveling to CARGILLS is Rs 25, find the net savings of Mr. X, using matrix multiplication method.

Expert's answer

Answer on Question #34412 – Math – Matrix | Tensor Analysis

Mr. X went to market to purchase 3kg3\mathrm{kg} of sugar, 10kg10\mathrm{kg} of wheat and 1kg1\mathrm{kg} of salt. In a shop, ARPICO near to Mr. X's residence, these commodities are priced at Rs 20, Rs 10 and Rs 8 per kg whereas in the local market, CARGILLS these commodities are priced at Rs 15, Rs. 8 and Rs 6 per kg respectively. If the cost of traveling to CARGILLS is Rs 25, find the net savings of Mr. X, using matrix multiplication method.

Solution

Denote by C1C_1 and C2C_2 vectors of prices in ARPICO and CARGILLS respectively. Then


C1=(20108);C2=(1586)C_1 = \begin{pmatrix} 20 \\ 10 \\ 8 \end{pmatrix}; \quad C_2 = \begin{pmatrix} 15 \\ 8 \\ 6 \end{pmatrix}


Let QQ denotes vector of amounts needed for Mr. X. Then


Q=(3101)Q = \begin{pmatrix} 3 \\ 10 \\ 1 \end{pmatrix}


Then the total price he pays equals to


Q′CiQ'C_i


Thus the difference between total prices in 2 shops equals to


Q′C1−Q′C2=Q′(C1−C2)Q'C_1 - Q'C_2 = Q'(C_1 - C_2)


Calculation:


Q′(C1−C2)=(3 10 1)[(20108)−(1586)]=(3 10 1)(522)=15+20+2=37Q'(C_1 - C_2) = (3 \ 10 \ 1) \left[ \begin{pmatrix} 20 \\ 10 \\ 8 \end{pmatrix} - \begin{pmatrix} 15 \\ 8 \\ 6 \end{pmatrix} \right] = (3 \ 10 \ 1) \begin{pmatrix} 5 \\ 2 \\ 2 \end{pmatrix} = 15 + 20 + 2 = 37


Since travelling to CARGILLS costs Rs 25 net savings equals to


37−25=1237 - 25 = 12


ANSWER: Rs 12

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