Answer to Question #95005 in Linear Algebra for LOGBON

Question

given that\\(A=\\begin{pmatrix}1 & 2 & 3\\\\ 4 & 5 & 6 \\end{pmatrix}\\)\nand \\[B=\\begin{pmatrix} 1 & 2\\\\ 3& 4\\\\ 5& 6 \\end{pmatrix}\\]\n. Find AB

Answer 1

$\begin{pmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \end{pmatrix}$ * $\begin{pmatrix} 1 & 2 \\ 3 & 4 \\ 5 & 6 \end{pmatrix}$ = $\begin{pmatrix} 1*1 + 2*3 + 3*5 & 1*2 + 2*4 + 3*6 \\ 4*1 + 5*3 + 6*5 & 4*2 + 5*4 + 6*6 \end{pmatrix}$ = $\begin{pmatrix} 22 & 28 \\ 49 & 64 \end{pmatrix}$