Answer to Question #87347 - Math – Linear Algebra
Question:
5. Given that A = ( 1 2 3 3 2 1 1 3 2 ) A = \begin{pmatrix} 1 & 2 & 3 \\ 3 & 2 & 1 \\ 1 & 3 & 2 \end{pmatrix} A = ⎝ ⎛ 1 3 1 2 2 3 3 1 2 ⎠ ⎞ . Find the determinant of A A A .
a. 2
b. 3
c. 1
d. zero
6. A matrix is said to be singular if the determinant is equal to
a. 3
b. 1
c. zero
d. 2
Solution:
5. ∣ A ∣ = ∣ 1 2 3 3 2 1 1 3 2 ∣ = 1 × ( 2 × 2 − 1 × 3 ) − 2 × ( 3 × 2 − 1 × 1 ) + 3 × ( 3 × 3 − 2 × 1 ) = 1 − 10 + 21 = 12 |A| = \begin{vmatrix} 1 & 2 & 3 \\ 3 & 2 & 1 \\ 1 & 3 & 2 \end{vmatrix} = 1 \times (2 \times 2 - 1 \times 3) - 2 \times (3 \times 2 - 1 \times 1) + 3 \times (3 \times 3 - 2 \times 1) = 1 - 10 + 21 = 12 ∣ A ∣ = ∣ ∣ 1 3 1 2 2 3 3 1 2 ∣ ∣ = 1 × ( 2 × 2 − 1 × 3 ) − 2 × ( 3 × 2 − 1 × 1 ) + 3 × ( 3 × 3 − 2 × 1 ) = 1 − 10 + 21 = 12 .
6. A matrix is said to be singular if the determinant is equal to zero.
Answer provided by https://www.AssignmentExpert.com