Question #82544

Let V = R3
, A = {(x, y,z)|y = 0} and B = {(x, y,z)|x = y = z}. Check whether
R3 = A⊕B

Expert's answer

Answer on Question #82544 – Math – Linear Algebra

Question

Let V=R3V = \mathbb{R}^3, A={(x,y,z)y=0}A = \{(x,y,z) | y = 0\} and B={(x,y,z)x=y=z}B = \{(x,y,z) | x = y = z\}.

Check whether R3=AB\mathbb{R}^3 = A \oplus B.

Solution

C=ABC = A \oplus B if and only if C=A+BC = A + B and AB=0A \cap B = 0.

1) (x,y,z)AB(x, y, z) \in A \cap B if and only if (x,y,z)A(x, y, z) \in A and (x,y,z)B(x, y, z) \in B, so

If (x,y,z)B(x,y,z)\in B then x=y=zx = y = z so (x,y,z)=(x,x,x)(x,y,z) = (x,x,x) and if (x,x,x)A(x,x,x)\in A then x=0x = 0 so (x,y,z)=(0,0,0)(x,y,z) = (0,0,0), so AB=0A\cap B = 0

2) (x,y,z)=(xy+y,y,zy+y)=(xy,0,zy)+(y,y,y)(x,y,z) = (x - y + y, y, z - y + y) = (x - y, 0, z - y) + (y, y, y)

(xy,0,zy)A(x - y, 0, z - y) \in A and (y,y,y)B(y, y, y) \in B so R3=A+B\mathbb{R}^3 = A + B

So, both conditions are true and R3=AB\mathbb{R}^3 = A \oplus B.

**Answer**: R3=AB\mathbb{R}^3 = A \oplus B holds true.

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