Question #80842

Which of the following are binary operations on S = {x ∈ R | x > 0}? Justify your answer. i) ii) The operation dened by xy=|ln(xy)| where lnx is the natural logarithm. The operation dened by xy=x2+y3

Expert's answer

Answer on Question #80842 – Math – Linear Algebra

Question

Which of the following are binary operations on S={xRx>0}S = \{x \in \mathbb{R} \mid x > 0\}? Justify your answer.

i) The operation defined by xy=ln(xy)x * y = |\ln(xy)| where lnx\ln x is the natural logarithm.

ii) The operation defined by xy=x2+y3x * y = x^2 + y^3.

Solution

An operation is binary if the result of performing the operation on a pair of elements of SS is again an element of SS.

Here both operations i) and ii) require 2 arguments (marked as xx and yy).

i) If we take x=y=1x = y = 1, then


xy=ln(11)=0.x * y = | \ln (1 - 1) | = 0.


In other words, xySx * y \notin S if xS,ySx \in S, y \in S.

Therefore, the operation defined by xy=ln(xy)x * y = |\ln(xy)| is not a binary operation.

ii) The operation defined by xy=x2+y3x * y = x^2 + y^3 is binary operation because x2+y3>0x^2 + y^3 > 0 if x>0,y>0x > 0, y > 0. In other words, xySx * y \in S if xS,ySx \in S, y \in S.

Answer: only ii) is a binary operation.

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